Sandbox Snake Eyes II

sewinglady's farm completed the event in 191 games. Still had ten games available so played them off, too, and collected all the booty that farm could from the star coin shop. PM23's farm got to #71 on the right side - just shy of that first piccolo box. This farm actually participated a little bit. Got a few nice things and one of the givers from the star coin shop. I figure it might come in handy in a future G&T.

 

thank you
i didn't even realize that there was a goliath beetle as a prize here and I had it

 

Finished in 197 games, played 202. Quite remarkable as I was away on holiday till yesterday.

I used Comfort Fields with SG and SSG to get a total (most days) of three harvests and occasionally nuked fields of 1x1s. I used a 100% Overall Bonus too but the Wheel wasn't kind to me at all.
I haven't had any luck with the Wonder Stables/Trees - in fact I had nearly all the same in each batch I put out. Very disappointing.
Good luck all those still rolling the dice.

 

Done. Finished the left side. Completed step 43 on the right. Played 117 games. That means 134.9 points a game. Since i have not been playing regularly for some years. I did not have the wonder stables of last 3 or 4 years. This event gave me 2 new stables which I feel is one of my best reward in this event. Happy.

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Something happened to the t in my keyboard. Lot of words were missing t. So edited. It must have been tthe water that got to my key board last week. One or more of my computer or laptop is foreever going to the computer mechanic for repair. Getting tired of that fact

 

I got 198 votes, I stayed at 92, I couldn't get the grand prizes, the time is running out, sorry.

 

Finished both side and did a few extra games hoping to get missing stables and or trees but to no avail. Only the usual suspects - perhaps that is why they are called Wonder - I always wonder why I don't get better results.

 

I have been researching Laws of Probability in an attempt to find the correct explanation for you.
The area concerned is whether the two events are independent or not. If I have to fail on the first, to get the second, then they are not independent.
The best I can come up with so far is that "Probability of an outcome is not influenced by what has happened before."
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I am gobsmacked with the rewards from my Piccolo boxes: One BB tree and one Magic tree!
For someone who made hardly any effort, I am still amazed at what I was able to achieve and the rewards reaped. I completed the left side, got all the CR givers and also used star coins for the Piccolo box. On the point side, I was able to get the Goliath beetle!

And yesterday must have been my day for trees because I also got a Suzy's Jumbo tree from a CR crate!

 

Congratulations, I gave 198 votes and stayed at 92, most of them passed without receiving any awards.

 

That's talking about mathematical independence, like if I flip a fair coin or roll a fair dice twice the outcome of the first flip/roll does not have any effect on the second. It's not talking about whether I choose to flip or roll the second time.

I think I can get you to understand this intuitively. Imagine that whenever you held two pairs you also got as many re-rolls as you liked. Say your pairs are 5 and 6. Do you expect to eventually roll either a 5 or 6, or do you still only have a 1/3 chance of a full house? Clearly you will eventually roll a 5 or 6. So more rolls do increase your chances.

Perhaps it would be clearer if I worked it out forwards rather than backwards. The chance you win on the first roll is 1/3. To win on the second roll you have to have lost on the first roll, as you rightly point out, so the odds of that are 2/3 (lose first roll) x 1/3 (win second roll). 2/3 x 1/3 = 2/9.

The overall odds are 1/3 + 2/9. Since 1/3 is the same as 3/9, that makes 3/9 + 2/9 = 5/9 = 0.56 in decimals. The same as the odds I got last time.

 

Someone mentioned stals, mysterys, I just mentioned that I have over 100 Neon and gold stable-mysteries combined. NEWER opened those... so, can say, I do not use stalss often, and then "alla areas sama stable, as many as I can" forexsample to do some Tigers last event, 40+41 and used 6 mighty movers and PW, quite many tiger in 12 hours, over 1000.

But trying to do Full House. With two pairs. 2/6 is persentage to get one of two´s in first try (when 2 pairs in first throw), if not right, second try also have 2 right and 4 wrong numbers. 2/6 + 2/6 = 4/6 so i think it is 4/6 = 66,66 % (yes 8 years on statictics in university) - I think that is not 56%

 

Hi yagmur,

I'm sorry you didn't achieve your goal.
I would love to send you a howie donut during Gift&Trade.

 

Thank you, no problem, I will look for targets in new events from now on.